T.R | Title | User | Personal Name | Date | Lines |
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47.1 | TLA and FLA | EAGLE1::EGGERS | Tom, 293-5358, VAX Architecture | Wed Jun 15 1988 21:06 | 3 |
| OK, I'll demonstrate my ignorance.
What is TDC? And BTDC?
|
47.2 | Answer to .1 ; to the best of my ability. | SCOMAN::CAPALDI | | Wed Jun 15 1988 22:11 | 4 |
| tdc stands for top dead center. Btdc stands for before top dead
center. This is the crankshafts reference to the timing marks when
the number one cylinder (in the firing order) is at the top of it's
stroke with both the intake and the exhaust valves closed.
|
47.3 | Here it is.. | HSK04::TILLANEN | Hyv�� jatkoa jos oma ei riit� ;-) | Thu Jun 16 1988 03:14 | 28 |
| Now, if my memory serves me right....the angle could be calculated
out of Pythagora's triangle (although there may be simplier ways
of doing the same). First of all; you must forgive me if some messy
terms occur, they are based on my lousy English.
What you have is a triangle which has one angle of 90 degrees, like:
/!<- this angle is what you want to know
/ !
Hypotenuse ---> / !<-- This kathete is refererred to as beta (�)
/ !
/____!<-- 90� (the right angle)
^
!
This is the kathete (or whatever it is in English) that
you get by measuring the TDC and BTDC (=the difference)
In geometry it is refereed as alpha (Sorry, no such
character on this terminal!)
You get the angle by getting Sin. of the alpha or Cos.
of the beta. (But you don't know the beta; just the
alpha!)
Hope this was of some help.
E T
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47.4 | you need to know | MSCSSE::BERENS | Alan Berens | Thu Jun 16 1988 10:17 | 6 |
| re .0:
As I recall from my motorcycle racing days when I when through the same
calculations: you must know the rod length (from wrist pin centerline to
crank journal centerline). Not what you wanted to hear, I guess.
|
47.5 | BTDC formula | HPSCAD::WHITMAN | Acid rain burns my BASS | Thu Jun 16 1988 10:27 | 7 |
|
Let 'x' = the distance below TDC where 'a' (the BTDC angle) is achieved
(i.e. how far off TDC you must move the piston vertically).
x = stroke/2 - ((cos a) * stroke/2)
Al
|
47.6 | We'll be timing tonight ! | MENTOR::REG | I fixed the boat; So, who want to ski ? | Thu Jun 16 1988 10:45 | 9 |
| re .5 Thanks Al, I knew I'd done it once before but had a
mental block about the con rod length having to be in there somewhere,
though I thought I'd got it to cancel out somewhow. I think this
is an approximation that only holds for small angles and reasonable
ratios of con rod length to stroke, but since thats the range of
interest it will probably work just fine.
Reg
|
47.7 | simple math indeed | SALEM::M_TAYLOR | I call it sin... | Thu Jun 16 1988 10:56 | 14 |
| Reg,
could it be this simple???
If you know the stroke length (and you claim to), van you not then
calculate in simple math degrees by distance moved? For example:
Assume a 3.75" stroke. Always, your stroke will take exactly 180
degrees. If you divide 3.75/180, you get the actual distance of
stroke per degree of crank rotation. in this example, one degree
of rotation equals .020833..."
I can't see why we need to go into trig'.
Mike
|
47.8 | Trig is Simple | DIXIE1::WILKINSON | Melted Snow Skier | Thu Jun 16 1988 11:38 | 4 |
| It's not linear. Piston will move up faster at mid stoke than at
bottem or top.
Nelson
|
47.9 | | BAGELS::DILSWORTH | Keith Dilsworth DTN 226-5566 | Thu Jun 16 1988 12:25 | 6 |
| I beleive the formula would be
Distance from TDC = stroke - ( cos(deg from TDC)*stroke)
-----------------------------------
2
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47.10 | Accuracy vs precision & practicallity. | MENTOR::REG | I fixed the boat; So, who want to ski ? | Thu Jun 16 1988 13:27 | 21 |
|
Oh, its very non linear.
Consider THE SHORTEST theoretical con rod possible, stroke/2,
this is theoretical because it would jam solid at 270 degrees from
TDC, since there would be no way to shove the piston back up, it
would just be pressed against the cylinder wall. Starting
from TDC the crank turns 90 degrees and the piston is at BDC, then
the crank turns another 180 degrees before the piston moves at all,
the last 90 degrees take it back up to TDC. Compare this to a very
long con rod (relative to the stroke), the piston/crank rotation
relationship is very similar between 90 - 270 to what it is between
270 - 90. Somewhere between these ridiculous extremes is a practical
con rod length, probably 1.x times the stroke, that has acceptable
side thrust and engine height (the most obvious trade off). I still
believe that the con rod : stroke ration matters, but only for large
angles. For ignition timing we're talking about <10 degrees (static),
so the approximation is fine.
Reg
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47.11 | Timimg | BPOV07::BURBINE | | Thu Jun 16 1988 13:55 | 11 |
| Come on folks we are supposed to be an engineering company. The
poor guy with the gage only has to drop in a rod mark the bottom,
mark the top then divide away. This technique is used in the real
world on diesels everyday to set the timing of the injector pump.
In order to be super accurate the dial indicator can be used with
a known extension to get to BDC.
Happy timing.
norm
|
47.12 | measure the con rod... | BINKLY::SMITH | | Thu Jun 16 1988 14:57 | 7 |
| If you are really worried about the length of the con rod and
do not wnt to rip apart the motor, how about going to a auto
parts store and requesting to see a con rod for you engine.
Measure it and hand it back to the guy, with a thank you.
Mike
|
47.13 | Use the tried and true method... | NRADM::WILSON | You have my word on it... | Thu Jun 16 1988 16:08 | 15 |
|
All this talk of measuring a spare connecting rod, complex
mathematical formulaes, etc. has made this into more of an
issue than it really is. Besides, any slight error in your
measurements or calculations could throw your timing setup
way off.
With the dial indicator you already have half of the tools
needed to do the job right. Degree wheels are not that expensive,
(less than 10 bucks I believe) and if you can't afford one
any decent engine builder would have one you could probably
make arrangements to borrow.
Rick W.
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47.14 | Betcha nobody beats this; simpliest way! | HSK04::TILLANEN | Hyv�� jatkoa jos oma ei riit� ;-) | Fri Jun 17 1988 03:00 | 5 |
| If you just want to set up the ignition timing then just forget
the formulas; go to a shop and buy a timing lamp. The timing marks
are usually on the flywheel or on the crankshaft.
E T
|