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Conference vmszoo::rc

Title:Welcome To The Radio Control Conference
Notice:dir's in 11, who's who in 4, sales in 6, auctions 19
Moderator:VMSSG::FRIEDRICHS
Created:Tue Jan 13 1987
Last Modified:Thu Jun 05 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:1706
Total number of notes:27193

592.0. "using 9v charger for 7.2v battery?" by AKOV11::KAUFMANN () Thu Jun 30 1988 11:15

    Can a 9V 120mA battery charger be used to charge a 7.2V 1200mA
    battery (overnight), without damaging the battery ?
    
    
T.RTitleUserPersonal
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592.1SNDCSL::SMITHTANSTAAIThu Jun 30 1988 12:466
    I would guess that it would do more damage to the charger than it
    would to the battery.  However, a [lessee] 15 ohm, 1/2 watt resistor
    in series should do the trick...
    
    Willie
    
592.2Not really...LEDS::LEWISThu Jun 30 1988 15:4024
    
    RE .0
    
    Maybe, but it's not worth trying.  When you say a 9v 120mA battery
    charger, I assume what you really mean is that it is designed to
    charge a 9v 120mAH battery.  Is that right?  If so, the charger
    probably puts out about 12ma of average current into 9v.
    
    To overnight charge a 1200mAH battery, you really want 120ma average
    current out of the charger.  This would probably require changing
    the series resistor inside the 9v charger, and chances are it will damage
    the transformer in the charger (there could actually be a risk
    of fire) because it is designed for only 1/10th of that current.
    
    It can actually hurt the battery to charge it with too low a
    current, so I wouldn't recommend trying to charge a 120mAH battery
    with much less than 100ma.

    So, go out and spend the bucks for the right charger, a good investment
    considering you pay 20 bucks for these batteries.  If you want to
    build your own simple charger to save a few bucks, you can
    do it with a transformer, diode and resistor.  Need any more details?
    
    Bill
592.3<>AKOV11::KAUFMANNThu Jun 30 1988 17:039
    
    
    Re .2
    
    Well the sticker on the charger says OUTPUT: DC 9V  120mA
    
    So, do your comments in .2 still apply ?
    
    
592.4You can use this charger with a simple modLEDS::WATTThu Jun 30 1988 18:5514
    You can use this charger if you drop the additional voltage across
    either a resistor or a handful of diodes.  Put an ammeter in series
    and measure the current, then add diodes until you get 120 mA. 
    Use any 1 amp diodes like 1N4004.  The battery will take 16 to 18
    hours to fully charge at that rate.  I charge my pack with a power
    supply and a resistor since I haven't invested in a suitable charger
    yet.  I just put a meter in series and adjust the power supply voltage
    to give me 120 mA.  The battery voltage stays pretty constant so
    the current doesn't change much.  If it changes, it tends to drop,
    so nothing will get smoked.  If you use a resistor, make sure that
    it has a sufficient power rating. 
    
    Charlie
    
592.5You're ok with 120ma ratingLEDS::LEWISFri Jul 01 1988 00:169
>>    Well the sticker on the charger says OUTPUT: DC 9V  120mA
>>    So, do your comments in .2 still apply ?

    Nope, that means it has a transformer that can put out the
    current you need.  The simple mod Charlie mentioned is fine.
    
    Bill
    
592.6Constant V and Constant ISNOC01::BROWNTONYTony Brown Sydney, AustraliaFri Jul 01 1988 03:1027
    
    I agree in general with Charlie, burt woild like to point out that
    most of these simple converters are (very roughly) designed to be
    constant voltage sources.  Ideally, nicads require constant current
    sources.  Hence, you require a source of 120 ma for 14 -16 hours,
    depending upon the initial state of charge of the battery.  I would
    guess that your charger is designed to give a constant 9v output,
    for currents up to 120ma.  Thus, as the battery gains charge, its
    voltage will rise and the current delivered by the charger will
    drop off, probably significantly.  The easiest way is to adopt
    Charlie's approach, but to be prepared to do some tweaking during
    the charging to keep the current up to a reasonable value.
    
    I think I've said this before, but please be careful and don't skimp
    on battery quality or charging procedures. My preference is for
    crashes to be caused by pilot error, as it is not too hard to minimize
    most other causes.  Why wreck many $$$$ and many hours work for
    the sake of a flight pack which isn't 100%?  This is hard for me
    to say as I've just shorted out a cell while making up a brand new
    pack.  I'm tempted to go ahead, but I will definitely use the cells
    for something else and buy four new ones. Cheap insurance.
    
    
    End of diatribe!!!!
    
    Tony
    
592.7A _BAAAAD_ PLACE TO SCRIMP.....PNO::CASEYATHE DESERT RAT (I-RC-AV8)Fri Jul 01 1988 11:4312
    I couldn't agree more. Tony.  The battery pack is the very heart
    and soul of the radio system and the very survival of you plane,
    boat or car depends on its health.  To shortcut battery pack quality
    and or charging in the interest of saving a buck or two is inviting
    disaster and will be _ultimately_ more expensive in the end than
    the coupla' bucks saved.    

      |
      | |      00	 Adios,      Al
    |_|_|      ( >o
      |    Z__(O_\_	(The Desert Rat)

592.8Testing the charge.IOENG::JWILLIAMSZeitgeist ZoologyFri Jul 01 1988 11:5312
    I would also add that it is a good idea to periodically test the
    battery for capacity. You can do this by charging it, then discharging
    it through a resistor. Keep a voltmeter across the resistor and
    record the voltage every minute or so. Since I = V/R, you can figure
    out the current. Integrate this over time, and voila, you have
    mAH. Now compare what you measured to what the battery advertises.
    If there's a significant difference, it's a fair guess that the
    battery is reaching the end of its life. You should do this maybe
    once every 5-10 charges, or whenever it's convenient. It is never
    convenient when the battery is in flight.
    
    						John.
592.9Know your charger!LEDS::LEWISFri Jul 01 1988 12:3268
    
>>  most of these simple converters are (very roughly) designed to be
>>  constant voltage sources.  Ideally, nicads require constant current...
     
>>  Thus, as the battery gains charge, its
>>  voltage will rise and the current delivered by the charger will
>>  drop off, probably significantly. 

    Just about every charger sold with radio systems today use this
    simple scheme - if you don't believe me open up your Futaba or
    Airtronics charger someday.  You'll see something like this :
    

              -----|>|-----/\/\/\/-----
                                       +
             ~                         -  (Batt)
              -------------------------
              

    Where ~ comes from a transformer and the resistor determines the
    charge current.  Effectively this _is_ like charging with a constant
    voltage source that depends on battery voltage to give you the proper
    average current.

    So it sounds like Tony is saying that people shouldn't use the charger
    that comes with the radio system - I don't agree, but do suggest
    that everyone check the charge current because some of them come quite
    a bit off from the ideal charge current of 1/10 C.

    Now as far as the question about using the 9v charger, it would
    actually be less susceptible to battery voltage variations (assuming
    it has a higher voltage transformer).  Take the two simple examples :
    
    		   ---/\/\/\----
                  +             +
                 Vin            Vout
                  -             -
                   -------------

    Let Vout = 7.2v and Vin = 10v (which you might have with a charger
    designed for charging a 7.2v battery.  The resistor you would want
    for 120ma is 
                   (10 - 7.2) / 120m = 23.3 ohms
    
    Now for Vin = 12v (which you might have with a charger designed
    for charging a 9v battery), the resistor is
    
                   (12 - 7.2) / 120m = 40.0 ohms
                    

    Ok, now lets say Vout rises 800mv during charging.  The charge current
    in the first case will drop to
    
                  (10 - 8.0) / 23.3 = 85.8 ma.  (29% drop)
    
    And in the second case the charge current drops to 
    
                  (12 - 8.0) / 40.0 = 100.0 ma. (20% drop)
    
    So if you're going to use a constant voltage charger you're better
    off with higher source voltage and higher series resistance.
    
    I can't argue that the best case is a constant current
    charger, but people have been using the chargers that come with
    their radio systems for many years without any trouble - and using
    the 9v charger presents no additional risk if properly modified.

    Bill
592.10I re-iterate...SNDCSL::SMITHTANSTAAIFri Jul 01 1988 13:4910
>      However, a [lessee] 15 ohm, 1/2 watt resistor
>    in series should do the trick...
 
    This will drop the voltage from 9 volts to 7.2 at 120 mA, keeping
    the current reasonably constant and disippating about 1/4 watt (so
    use a 1/2 watt resistor).  You don't need to fool around with diodes
    and such....
    
    Willie
    
592.11great feedbackAKOV11::KAUFMANNFri Jul 01 1988 15:415
    Thanks for the feedback, it's been very educational.
    I will experiment with the 1/2 watt resistor mod.
    
     
    
592.12RC chargersSNOC01::BROWNTONYTony Brown Sydney, AustraliaSun Jul 03 1988 19:5312
    
    re .9
    
    I'm not criticizing the chargers that come with the radios as I
    haven't looked inside any of the Japanese ones.  I'm just advocating
    a little caution when using what appears to be a non standard item.
    
    Good luck.
    
    Tony
    
    
592.13Chargers that come with radios are nothing specialLEDS::WATTTue Jul 05 1988 13:0721
    I'd like to reaffirm what BIll said here.  The chargers that come
    with radios are nothing special.  They are very simple and cheap.
    Almost any other charger is as good if you monitor the current and
    find it to be correct.  For example, let's say your line voltage
    is a little high or low.  None of the chargers that come with radios
    have regulation in them, so your charge current will be high or
    low.  Nicads can be damaged due to overcharge if you charge them
    at a current greater than .1 times their mAH rating.  Also, if one
    cell in your pack shorts out, the charger will now overcharge the
    remaining cells.  If you are not monitoring your battery voltage
    occasionally, this can happen to you!  Your transmitter and your
    reciever will still function normally with one cell shorted.  You
    will not know that you have a problem until another one goes.
    Therefor it is wise to check your charger's charge current frequently
    and to check your battery voltage and capacity at least a couple
    of times during the flying season.  Our radio equipment works very
    well until the batteries fail.  Don't have it happen to you while
    in flight.
    
    CHarlie