T.R | Title | User | Personal Name | Date | Lines |
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5058.1 | | M5::JHAYTER | | Fri Feb 21 1997 10:22 | 7 |
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>This appears to happen when many (around 20) recovery processes are
>started.
what is the "Default recovery buffer count"?
I don't know if recovery processes can exceed the user limit.
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5058.2 | | NOVA::R_ANDERSON | Oracle Corporation (603) 881-1935 | Fri Feb 21 1997 15:42 | 5 |
| Well, the obvious guess would be that DBR requires buffers in addition to the
dead user's (who isn't really quite dead yet :-), and DBR requires MORE buffers
(typically) than the dead user.
Rick
|
5058.3 | It didn't appear so | svrav1.au.oracle.com::MBRADLEY | I was dropped on my head as a baby. What's your excuse? | Wed Feb 26 1997 21:16 | 12 |
| >Well, the obvious guess would be that DBR requires buffers in addition to the
>dead user's (who isn't really quite dead yet :-), and DBR requires MORE buffers
>(typically) than the dead user.
This does not appear to be the case. The monitor log shows the failed user
relinqishing his buffers prior to the DBR grabbing them. I will see if I
can get an extract of the monitor log file to show you, but that may take a
few days.
G'day,
Mark.
|
5058.4 | Just taking aother look at this | svrav1.au.oracle.com::MBRADLEY | I was dropped on my head as a baby. What's your excuse? | Sun Mar 16 1997 21:07 | 22 |
| Rick,
> <<< Note 5058.2 by NOVA::R_ANDERSON "Oracle Corporation (603) 881-1935" >>>
>
>Well, the obvious guess would be that DBR requires buffers in addition to the
>dead user's (who isn't really quite dead yet :-), and DBR requires MORE buffers
>(typically) than the dead user.
Well in my testing, the DBR always uses the same number of buffers as the
failed user. The only thing that would make sense is if the failed user was
on another node. Then you would get the DBR taking additional buffers on
the recovery node.
But I still can't see how we could run out of buffers when the limit seems
to be the number of users.
I am getting them to look at the monitor log to see if the failed user was
on the same node as the DBR, but either way it doesn't seem to make sense.
G'day,
Mark.
|