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| Title: | MAILBUS 400 User Forum |
| Notice: | kits 100-109 - Infocenter //www.digital.com/info/messaging |
| Moderator: | IOSG::MARSHALL |
|
| Created: | Thu Jun 11 1992 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 3210 |
| Total number of notes: | 9174 |
3192.0. "MAILBUS400 -> LMS problem" by JOBURG::BERETTA () Wed May 14 1997 15:18
Hi,
My customer is having a problem talking to an LMS (Lotus Mail System
formerly Softswitch). They have a problem when Mailbus 400 sends them
a large message > than 30k. The failure can be controlled by changing
the checkpoint size. If the checkpoint size is set 1 on the LMS system,
all messages fail. If it is set to 7, then only large messages fail.
They get a message saying "invalid length" (I entered a note 3184 when
we thought it was exchange causing the problem, but it seems to be LMS
that is the problem) Below is a trace with annotation from one of the
LMS support engineers:
Here's an X.25 trace showing the problem. It looks like a problem
with the interpretation of the P layer, but I am very unclear how it is
meant to be interpreted. Are PPDUs embedded within SPDUs or do they span
them?
The trace run's as follows (with anotation):
....
Various packets establishing connection from OMS -> LMS. Now we start
receiving a message from OMS:
...
Rx - SNID=A (14:51:37.8)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 3/3
X) Bits: D Q M 0 0 0
X) 02 F0 80 01 00 2D 05 29 03 02 01 01 .....-.)....
X) Protocol: ISO-CONS
Rx - SNID=A (14:51:37.12)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 4/4
X) Bits: D Q M 0 0 1
X) 02 F0 00 01 00 01 00 61 80 30 80 02 01 3D A0 80 .......a.0...=..
X) 04 82 14 00 28 80 02 01 3F A0 80 A0 80 31 80 64 ....(...?....1.d
X) 80 63 80 61 80 13 02 5A 41 00 00 62 80 13 09 54 .c.a...ZA..b...T
X) 45 4C 4B 4F 4D 34 30 30 00 00 00 00 16 18 43 31 ELKOM400......C1
X) 35 37 45 31 44 45 31 31 44 30 43 39 34 34 30 30 57E1DE11D0C94400
X) 30 38 30 39 38 30 00 00 60 80 30 80 61 80 13 02 080980..`.0.a...
X) 5A 41 00 00 62 80 13 09 54 45 4C 4B 4F 4D 34 30 ZA..b...TELKOM40
X) 30 00 00 83 09 54 45 4C 4B 4F 4D 20 53 41 A5 80 0....TELKOM SA..
X) Protocol: ISO-CONS
Tx - SNID=A (14:51:37.12)
X) >>>> Receive Ready <<<<
X) Channel: 001
X) P(R): 5
Rx - SNID=A (14:51:37.16)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 5/5
X) Bits: D Q M 0 0 1
X) 80 07 46 61 72 72 65 6C 6C 81 04 4D 61 72 6B 00 ..Farrell..Mark.
X) 00 00 00 31 80 30 80 80 01 01 A1 80 13 0C 4D 61 ...1.0........Ma
X) 72 6B 20 46 61 72 72 65 6C 6C 00 00 00 00 00 00 rk Farrell......
X) 00 00 65 80 A4 80 06 07 28 CE 25 07 01 00 4D 06 ..e.....(.%...M.
X) 07 28 CE 25 07 01 00 64 06 07 28 CE 25 07 01 00 .(.%...d..(.%...
X) 01 06 07 28 CE 25 07 01 00 06 00 00 80 02 00 00 ...(.%..........
X) 00 00 46 01 16 4A 10 55 30 31 31 33 37 2D 37 35 ..F..J.U01137-75
X) 41 4F 33 44 30 30 34 47 01 00 48 02 00 20 A2 80 AO3D004G..H.. ..
X) Protocol: ISO-CONS
Rx - SNID=A (14:51:37.18)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 6/6
X) Bits: D Q M 0 0 1
X) 31 80 60 80 30 80 61 80 13 02 5A 41 00 00 62 80 1.`.0.a...ZA..b.
X) 13 09 54 65 6C 6B 6F 6D 34 30 30 00 00 A2 80 13 ..Telkom400.....
X) 06 74 65 6C 6B 6F 6D 00 00 A5 80 80 03 65 6D 67 .telkom......emg
X) 00 00 00 00 00 00 80 01 01 81 02 00 D0 A3 80 30 ...............0
X) 80 80 01 06 81 02 05 00 A2 80 30 80 02 01 00 00 ..........0.....
X) 00 00 00 00 00 00 00 00 00 00 00 69 80 30 80 63 ...........i.0.c
X) 80 61 80 13 02 5A 41 00 00 62 80 13 09 54 45 4C .a...ZA..b...TEL
X) 4B 4F 4D 34 30 30 00 00 00 00 31 80 80 0D 39 37 KOM400....1...97
X) Protocol: ISO-CONS
Tx - SNID=A (14:51:37.18)
X) >>>> Receive Ready <<<<
X) Channel: 001
X) P(R): 7
Rx - SNID=A (14:51:37.29)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 7/7
X) Bits: D Q M 0 0 1
X) 30 35 31 30 31 34 35 30 33 33 5A 82 01 00 65 80 0510145033Z...e.
X) 80 02 00 20 00 00 00 00 00 00 00 00 00 00 04 82 ... ............
X) ED DE A0 80 31 80 6B 80 13 10 55 30 31 31 33 37 ....1.k...U01137
X) 2D 37 35 41 4F 33 44 30 30 34 00 00 A0 80 60 80 -75AO3D004....`.
X) 30 80 61 80 13 02 5A 41 00 00 62 80 13 09 54 45 0.a...ZA..b...TE
X) 4C 4B 4F 4D 34 30 30 00 00 83 09 54 45 4C 4B 4F LKOM400....TELKO
X) 4D 20 53 41 A5 80 80 07 46 61 72 72 65 6C 6C 81 M SA....Farrell.
X) 04 4D 61 72 6B 00 00 00 00 31 80 30 80 80 01 01 .Mark....1.0....
X) Protocol: ISO-CONS
Rx - SNID=A (14:51:37.32)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 0/0
X) Bits: D Q M 0 0 1
X) A1 80 13 0C 4D 61 72 6B 20 46 61 72 72 65 6C 6C ....Mark Farrell
X) 00 00 00 00 00 00 00 00 00 00 A2 80 31 80 A0 80 ............1...
X) 60 80 30 80 61 80 13 02 5A 41 00 00 62 80 13 09 `.0.a...ZA..b...
X) 54 65 6C 6B 6F 6D 34 30 30 00 00 A2 80 13 06 74 Telkom400......t
X) 65 6C 6B 6F 6D 00 00 A5 80 80 03 65 6D 67 00 00 elkom......emg..
X) 00 00 00 00 80 03 65 6D 67 00 00 81 02 05 00 00 ......emg.......
X) 00 00 00 A8 80 14 13 48 65 6C 6C 6F 20 4D 61 72 .......Hello Mar
X) 6B 20 41 47 41 49 4E 21 21 21 00 00 8C 01 01 8E k AGAIN!!!......
X) Protocol: ISO-CONS
Tx - SNID=A (14:51:37.32)
X) >>>> Receive Ready <<<<
X) Channel: 001
X) P(R): 1
Rx - SNID=A (14:51:37.37)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 1/1
X) Bits: D Q M 0 0 1
X) 01 00 00 00 30 80 A0 80 31 80 80 01 05 00 00 16 ....0...1.......
X) 82 EC E7 0A 52 45 41 44 4D 45 2E 54 58 54 20 0D ....README.TXT .
X) 0A 0D 0A 4E 4F 54 45 53 20 4F 4E 20 4D 53 2D 44 ...NOTES ON MS-D
X) 4F 53 20 36 2E 32 32 0D 0A 3D 3D 3D 3D 3D 3D 3D OS 6.22..=======
X) 3D 3D 3D 3D 3D 3D 3D 3D 3D 3D 3D 3D 3D 0D 0A 54 =============..T
X) 68 69 73 20 66 69 6C 65 20 70 72 6F 76 69 64 65 his file provide
X) 73 20 69 6D 70 6F 72 74 61 6E 74 20 69 6E 66 6F s important info
X) 72 6D 61 74 69 6F 6E 20 6E 6F 74 20 69 6E 63 6C rmation not incl
X) Protocol: ISO-CONS
...
...
...
Lot's of X.25 packets elided from the trace, containing more of the same
IA5 body part...
...
...
...
Rx - SNID=A (14:51:38.72)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 3/3
X) Bits: D Q M 0 0 0
X) 70 72 65 73 73 65 64 20 66 6C 6F 70 70 79 20 64 pressed floppy d
X) 69 73 6B 0D 0A 20 20 20 37 2E 32 34 20 41 75 74 isk.. 7.24 Aut
X) 6F 6D 6F 75 6E 74 69 6E 67 20 61 6E 64 20 4E 6F omounting and No
X) 72 74 6F 6E 20 44 69 73 6B 20 43 61 63 68 65 0D rton Disk Cache.
X) 0A 20 20 20 37 2E 32 35 20 55 6E 64 65 6C 65 74 . 7.25 Undelet
X) 65 20 75 74 69 6C 69 74 69 65 73 20 61 6E 64 20 e utilities and
X) 44 72 69 76 65 53 70 61 63 65 0D 0A 20 20 20 37 DriveSpace.. 7
X) 2E 32 36 20 43 72 65 61 74 69 6E 67 20 61 6E 20 .26 Creating an
X) Protocol: ISO-CONS
Rx - SNID=A (14:51:38.72)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 4/4
X) Bits: D Q M 0 0 0
X) 02 F0 80 45 6D 65 72 67 65 6E 63 79 20 53 74 61 ...Emergency Sta
X) 72 74 75 70 20 44 69 73 6B 20 66 6F 72 20 44 72 rtup Disk for Dr
X) 69 76 65 00 00 00 00 00 00 ive......
X) Protocol: ISO-CONS
Now, what are the final 6 zeros in the previous packet? Are they closures
of the PPDU indefinite constructs at the start of the message or are they
extra gash data?
Next few packets are:
Tx - SNID=A (14:51:38.73)
X) >>>> Receive Ready <<<<
X) Channel: 001
X) P(R): 5
Rx - SNID=A (14:51:38.77)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 5/5
X) Bits: D Q M 0 0 0
X) 02 F0 80 01 00 31 03 2A 01 31 .....1.*.1
X) Protocol: ISO-CONS
Tx - SNID=A (14:51:38.79)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 3/3
X) Bits: D Q M 0 0 0
X) 02 F0 80 02 00 32 03 2A 01 31 .....2.*.1
X) Protocol: ISO-CONS
Rx - SNID=A (14:51:38.82)
X) >>>> Data <<<<
X) Channel: 001
X) P(R)/P(S): 6/6
X) Bits: D Q M 0 0 1
X) 02 F0 00 01 00 01 00 61 80 30 80 02 01 3D A0 80 .......a.0...=..
X) 04 82 14 00 53 70 61 63 65 20 53 79 73 74 65 6D ....Space System
X) 73 0D 0A 20 20 20 37 2E 32 37 20 49 66 20 53 63 s.. 7.27 If Sc
X) 61 6E 44 69 73 6B 20 43 61 6E 6E 6F 74 20 43 68 anDisk Cannot Ch
X) 65 63 6B 20 6F 72 20 52 65 70 61 69 72 20 61 20 eck or Repair a
X) 44 72 69 76 65 53 70 61 63 65 20 56 6F 6C 75 6D DriveSpace Volum
X) 65 20 46 69 6C 65 0D 0A 0D 0A 0D 0A 31 2E 20 53 e File......1. S
X) 45 54 55 50 0D 0A 3D 3D 3D 3D 3D 3D 3D 3D 0D 0A ETUP..========..
X) Protocol: ISO-CONS
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