Title: | Brain Bogglers |
Notice: | BRAIN_BOGGLERS is, like, back in business, totally |
Moderator: | BUSY::SLAB |
Created: | Mon Jul 13 1987 |
Last Modified: | Mon Jun 02 1997 |
Last Successful Update: | Fri Jun 06 1997 |
Number of topics: | 1441 |
Total number of notes: | 13981 |
Start with a 3D rectangular box [Kleenex box, for example] and crush both the short ends towards the center of the box. You will end up [roughly] with a hexagon. What are the relative box dimensions that will result in a perfect hexagon? You might want to try this to see exactly what happens to the box.
T.R | Title | User | Personal Name | Date | Lines |
---|---|---|---|---|---|
1435.1 | kind of a funny crush, though | NETCAD::ROLKE | The FDDI Genome Project | Tue Feb 25 1997 17:09 | 7 |
although it seems to be a lot easier to make an octagon. Chuck h=0.5 w=1 l=sqrt(3) | |||||
1435.2 | BUSY::SLAB | Antisocial | Tue Feb 25 1997 17:51 | 7 | |
Hmmm, maybe it WAS an octagon. 8^) I know it had at least 6 sides. | |||||
1435.3 | 4446::OSMAN | Eric Osman, dtn 226-7122 | Thu Apr 03 1997 17:06 | 13 | |
Which reminds me: Take a long narrow strip of paper (the perforated side strips from some computer printouts are perfect). Carefully tie it in an overhand knot, and gently pull until tight but don't tear. Flatten it out, and you have a perfect pentagon ! (If you see me in person, I'll tell you how to use this idea to nice 3-d stars, but I don't think I can explain it in the notes file) /Eric |