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Conference netcad::hub_mgnt

Title:DEChub/HUBwatch/PROBEwatch CONFERENCE
Notice:Firmware -2, Doc -3, Power -4, HW kits -5, firm load -6&7
Moderator:NETCAD::COLELLADT
Created:Wed Nov 13 1991
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:4455
Total number of notes:16761

3238.0. "Find Duplicate problem" by HGOVC::SIUKEUNGLEE () Mon Feb 05 1996 10:19

    Hi,
    
    Refer to 2548 duplicate address problem. If two or more repeater are
    connected together like the following configuration:
    
    		-----		-----		-----
    		| D |		| D |		| D |
     PC --------| R |		| R |		| R |---- Hubwatch 
    		| 9 |		| 9 |		| 9 |
    		| 0 |-----------| 0 |-----------| 0 |
       		| 0 |		| 0 |		| 0 |
    		| 0 |		| 0 |		| 0 |
    		-----		-----		-----
                 R1		 R2		 R3
    		
    If the PC send some packets though R1 to R3. Refer to 2548, 
    all the repeaters wil keep the PC's MAC address in their
    erptrAddrDBPortAddrtable. Then the Hubwatch run the "Find Duplicate"
    will obtain the result like in 2548.0.
    
    Could someone tell me my understanding is right or wrong ? If wrong, 
    please give me some example and detail explain.
    
    Thank very MUCH!
    
    David Lee.
    HKMCS.
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