T.R | Title | User | Personal Name | Date | Lines |
---|
2008.1 | Additional info ... | RAVEN1::JERRYWHITE | Joke 'em if they can't take a ... | Wed Oct 24 1990 07:09 | 8 |
| The crossover is rated at 100W (it's a Radio Shack job, so that's
probably about 70W in reality ...).
The power amp I'm using will be a 60W job.
A 4ohm load wouldn't hurt the amp any ...
Scary
|
2008.2 | | AQUA::ROST | Neil Young and Jaco in Zydeco Hell | Wed Oct 24 1990 10:37 | 7 |
| Electrically, tapping at the output of the crossover or at the speaker
terminals is identical...???? Did I understand you correctly?
Assuming your drivers are all 8 ohms, the crossover will see 4 ohms at
each tap.
Brian
|
2008.3 | OK, who stole the mids? | LEDS::ORSI | Tripe my shorts | Wed Oct 24 1990 11:37 | 33 |
|
Scary, I hate to tell you this, but you can't do that without
having major problems.
For example, if you had an 800Hz 6dB/oct 8 ohm crossover,
it would consist of a 1.6mH inductor (L) and a 25mf capacitor (C)
If you could graph its response, it would look something like
this:
800Hz
--------------------------- -----------------------
Bass \/ < 3dB down point
8 ohm spkr /\
/ \ Treble
/ \ 8 ohm spkr
If you put a 4 ohm load across the same crossover, the response
would be somewhat different:
400Hz 1600Hz
------------------- ---------------
Bass \ Midrange / Treble
4 ohm spkrs \ is / 4 ohm spkrs
\ essentially /
\ wiped out /
Inductor and Capacitor values are selected according to speaker specs,
cabinet design, nominal load impedance, required rolloff: 1st, 2nd,
or 3rd order, i.e. 6, 12, or 18dB/oct slope
Hope this helps :^)
Neal
|
2008.4 | Two ends of the same piece of wire | MILKWY::JACQUES | Vote Yes on 3 | Wed Oct 24 1990 12:36 | 23 |
| That's what I'm saying. perhaps a picture would help make my point
+ --------------- + /
C High || Tweeter
R - --------------- - \
O
S + --------------- + /
S Mid || Mid range driver
O - --------------- - \
V
E + --------------- + /
R Bass || Woofer
- --------------- - \
Electrically, aren't the speaker terminals considered the same
"node" as the crossover (output) terminals ? If a jack were connected
in parallel with either the crossover terminals or speaker terminals,
wouldn't the result be the same ? There is a piece of WIRE connecting
the terminals together. How could they be differant electrical nodes ?
Mark
|
2008.5 | But what do I know .... | RAVEN1::JERRYWHITE | Joke 'em if they can't take a ... | Wed Oct 24 1990 13:03 | 7 |
| Seems to me (spoken by the guy that has to look at the diagram when
putting batteries in a flashlight ..) that I could jumper off the
speakers, going positive to positive, etc, and still be OK. Lemme know
guys, 'cuz I wanna try *something* in a little while after I "get up" -
no smart remarks ... I'm a 3rd shifter ! 8^)
Scary (who's up but really doesn't know why ...)
|
2008.6 | | LEDS::ORSI | Tripe my shorts | Thu Oct 25 1990 14:47 | 32 |
|
I understand what you are asking, Mark, and the answer is
no. Because the whole operation of the crossover is determined
by the LOAD impedance on each leg of the filter, not what the
amp sees at the input of the crossover. You can determine what
the amp sees at the input of the crossover if you were to
design a 4 ohm crossover. In that case, the value of the cap
doubles, and the value of the inductor is cut in half...for
each leg.
Rat Shack crossovers are overrated power-wise, and saturate
much too soon when pushed. The thin copper wire in the coils
is the problem. You can tell when a shi++y crossover starts
to crap out when the mids and highs fade when the band is
cranking and mysteriously comes back between songs when your
lead singer is just talking to the crowd. It's because the
bass speakers suck alot more power to reproduce the lower
frequencies and the mids and highs suffer. If it's only a
6dB/oct crossover, you may be getting alot more low end into
the mid and high drivers than they can handle, even if you
can't exactly hear it. 2nd order (12dB/oct), and 3rd order
(18dB/oct) crossovers have sharper cutoff rates to keep things
safe. Big coils made from 16 or 14 gauge wire, and 250 volt caps
in a crossover makes saturation less likely, but are still
inefficient. You can lose ~20% of the power available. Also
a pad, or an attenuation network, is needed at the mid and
high outputs of a crossover to balance them with the bass cone
driver, which isn't as loud. L-pads are available at RS for
this purpose.
Neal
|
2008.7 | More stoopid questions ... | RAVEN1::JERRYWHITE | Joke 'em if they can't take a ... | Mon Oct 29 1990 04:47 | 6 |
| I fixed my problem - I bought another crossover and wired it right !
Now, I'd like to wire in a couple jacks so I can jump from 1 cab to the
other. Do I just put jumpers off the "input" jack (pre-crossover) to
the second (out) jack ? Sounds good to me, but ....
Scary
|
2008.8 | Should be OK now | LEDS::ORSI | Tripe my shorts | Mon Oct 29 1990 08:45 | 7 |
|
Re .7
Yeah, but use 16 gauge wire or better.
Neal
|
2008.9 | | RAVEN1::JERRYWHITE | Joke 'em if they can't take a ... | Mon Oct 29 1990 08:47 | 7 |
| You guys be patient with me, OK ?
Rat Shack sells "closed circuit" jacks (?) and "open circuit" jacks (?)
Which kind do I need ?
Scary (who's learnin' ...)
|
2008.10 | | AQUA::ROST | Neil Young and Jaco in Zydeco Hell | Mon Oct 29 1990 10:13 | 6 |
|
Open circuit. Closed circuit jacks are used in things like headphone
jacks, inserting the plug into the jack causes a switching action (like
turning the speakers off on a stereo).
Brian
|