Conference napalm::guitar

    
    	First of all, you're not going to ruin your amp by putting
    a line level into the input. Plugging the *AC* line into the input
    of your amp might do the job, but the levels of the walkman will
    not. It may sound distorted, however, as the level *is* considerably
    higher than that from a guitar. You need about a 10:1 reduction, 
    which can be accomplished with a resistor divider network containing 
    2 resistors. If you want to "mix" the stereo outputs of the walkman 
    together for a single mono signal, you'll need three resistors.
    
    	Without going into the details of the physical construction,
    I would get the appropriate parts plus two 47K ohm resistors and
    one 4.7K ohm. This will load the line outs to about 50K ohms, which
    is an easy load for the walkman to drive. If you use a metal box,
    the "ground" or "shield" of the cabling will all be common - this
    is what I'd recommend.
    
    	Left out <---------/\/\/\/\--------
                                          |-----/\/\/\/\------->"ground".
    	Right out <--------/\/\/\/\--------       4.7K
    			      47K (Both)  |
    					  |
    					  |
    					  ^
    					Guitar amp.
    
    	The "schematic" of the line level reducer looks like this. The
    output to the guitar amp is taken from the junction of all three
    resistors. The 4.7K resistor *must* connect to ground for this to
    work. Good Luck with your project!
    
    	Joe Jas                                 

    Going the other way...
    
    How about an adaptor to connect �" jack from the guitar to separate
    Left and Right connectors to plug into a pre-amp on a home stereo?
    
    I don't have a guitar amp but would like to play a guitar through
    my home system.
    
    Mike

    
     Radio Shack lists a 1/4" to RCA phono adapter.

    Orrrr, better yet..
    
    search the want adds and by urself a second hand Rockman, and use
    *that* with your walkman, and into headphones....
    
    Indispensible for learning songs in my book...
    
    Probably get away cheap if you look hard enuff..
    
    

    
    Re: .2
    
    It's been said before, but I'll say it again....Use caution when
    playing guitar through stereo systems.  In particular be careful
    to avoid boosting the bass.  Home speakers are not as rugged as
    guitar amp speakers and can be blown easily.  When in doubt, keep
    the volume down or use headphones.
    
    

    
    
    	RE: .1, thanks again... built this patch cable this weekend
    and it works fine (BTW, there is plenty of room inside a 1/4" phone
    jack for the 4.7k... I wired it across the leads inside the jack).
     The only change I'd make (if I could) would be to create a little
    more volume for the cassette.  It used to distort no matter what
    level it was at (without the divider)... now I wish it were just
    a skosh higher....  Don't tell me the answer though, cos this little
    item is one more (GOOD?) reason for me to buy that Princeton Chorus
    that I truly need... <grin>..
    
    
    Steve

    Re: .6
    
    Use a smaller resistor value to get more volume.  Replace the 47Ks
    with a 22K or 33K, for instance.

    
    
    	And leave the 4.7k going to ground??
    
    U gotta take us dummies by the hand <grin>

    
    Yes, you just replace the two 47K ohm resistors in the original circuit
    with lower valued ones (like 22K).  What we have here is a resistive
    divider. 
    
    You have the signal going through a 47K ohm resistor then a 4.7K
    ohm resistor to ground.  By the principle of superposition, we can
    consider each channel (left and right) as totally independent.
    
    Ohm's law says V=IR, and in a series connection the current I is
    constant. Since the 47K ohm resistor is ten times the 4.7K, you get
    1/11 of the original signal passed into the amp: 
    
    V(walkman) = (47,000 X I1) + (4700 X I1)

    where V(amp) equals 4700 X I1.
    
    Now, if we switch to 22K ohms, we get about 1/5 of the original signal
    passed to the amp (or roughly twice as much signal as before): 
    
    V(walkman) = (22,000 X I2) + (4700 X I2)    

    now V(amp) equals 4700 X I2.  Since V(walkman) is constant, it's
    easy to see that I2 will be larger, therefore, V(amp) will be greater.

    
    
    	EXCELLENT EXPLANATION!!!  Thanks, soooo.. if I were to replace
    the two 47k with, ohhhhh, say a 100k ohm pot (although I don't know
    if such a thing exists) then I could vary the output with the pot,
    right??
    
    Steve

    
    Re: .11
    
    Yes, but of course you either need *two* pots, or else a stereo
    pot (two pots on a common shaft).