T.R | Title | User | Personal Name | Date | Lines |
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2060.1 | complex numbers? | FLOYD::YODER | MFY | Fri Aug 30 1996 17:29 | 14 |
| I think that "all" you get are complex numbers. That is, if
x = arcsinh(2)
then
ix = arcsin(2)
is "merely" an imaginary number.
So your second example is arguably the same as the first!
ix -ix
In C, sin(x) = (e - e )/2i.
|
2060.2 | | RUSURE::EDP | Always mount a scratch monkey. | Tue Sep 03 1996 09:42 | 11 |
| In Derive (or most symbolic math packages), enter asin(2) and simplify
to get:
pi/2 - i ln(sqrt(3)+2).
-- edp
Public key fingerprint: 8e ad 63 61 ba 0c 26 86 32 0a 7d 28 db e7 6f 75
To find PGP, read note 2688.4 in Humane::IBMPC_Shareware.
|
2060.3 | if sin(a) = 2 then ... | PAWN21::OSMAN | see HANNAH::IGLOO$:[OSMAN]ERIC.VT240 | Tue Sep 03 1996 10:51 | 16 |
|
sin(a) = 2
sin^2 + cos^2 = 1
so
2^2+cos^2 = 1
cos^2 = -3
cos(a) = sqrt(-3)
Does this help ?
/Eric
|
2060.4 | re: .3 | BEGIN::YODER | MFY | Tue Sep 03 1996 11:18 | 9 |
| >Does this help?
It helps in that it suggests that the arcsin(2) extension might be
related to the sqrt(-1) extension (and we know that it is).
You have hit upon a problem that happens to be solved, though I
wouldn't mind if this turned into a discussion of functions over
the complex plane (especially if it became a discussion of
algorithms).
|