| Title: | Mathematics at DEC |
| Moderator: | RUSURE::EDP |
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
Show that the sum of any 1996 consecutive integers cannot be a power of
an integer with exponent greater than one.
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 2047.1 | IOSG::CARLIN | Dick Carlin IOSG, Reading, England | Mon May 20 1996 06:51 | 12 | |
Sum of a ... a+1995 is
998(2a+1995)
= 2 * 499 * (2a+1995)
This has a factor of 2, with exponent 1 only.
Dick
I've left out a step which is "obvious" but not entirely trivial to
prove (p|x^n -> p|x).
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