| Title: | Mathematics at DEC |
| Moderator: | RUSURE::EDP |
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
hi all
a friend of mine asked me to solve this differential equation:
dv
m * -- = m*g - k*v
dt
where m = mass
v = velocity
g = the well known constant
k = constant
any help ... I need something like v(t) = ....
thanks
Luciano
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 1811.1 | HERON::BUCHANAN | The was not found. | Fri Oct 29 1993 10:32 | 15 | |
> dv > m * -- = m*g - k*v > dt / mdv / |----- = | dt /mg-kv / Let u be the value of v at t=0, then: v = mg/k + (u-mg/k)*e^(-tk/m) mg/k is the terminal velocity. Andrew. | |||||
| 1811.2 | thanks | PDV01::MEDONI | Fri Oct 29 1993 11:20 | 1 | |