| Title: | Mathematics at DEC |
| Moderator: | RUSURE::EDP |
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
What kind of series or transformation happens with the following:
(real_number)/( (exponential(log(2)) * (binary_scale_factor))
thanks
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 1780.1 | Doesn't seem to make sense as is. | CADSYS::COOPER | Topher Cooper | Thu Aug 12 1993 18:57 | 15 |
You sure you have that right?
If the base for the log is e, which is standard, then
exponential(log(2)) = 2
However:
exponential(log(2) * binary_scale_factor)
is a way of calculating 2^binary_scale_factor (where x^y is x raised
to the y power). Then the whole thing would become a division of the
real_number by a power of 2.
Topher
| |||||
| 1780.2 | re .1 | AUSSIE::GARSON | nouveau pauvre | Thu Aug 12 1993 19:14 | 1 |
...an excruciatingly slow way of doing it | |||||
| 1780.3 | re .2 | CADSYS::COOPER | Topher Cooper | Fri Aug 13 1993 16:06 | 4 |
...unless if "binary_scale_factor" is non-integral, in which case it is
a common way of doing it
Topher
| |||||