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| Title: | Mathematics at DEC |
|
| Moderator: | RUSURE::EDP |
|
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
1664.0. "CMJ Problem 485" by BEING::EDP (Always mount a scratch monkey.) Fri Sep 11 1992 10:56
Prove that
i) if a >= b > 1 or 1 > a >= b > 0, then
a^b^b*b^a^a >= a^b^a*b^a^b; and
ii) if a > 1 > b > 0, then a^b^b*b^a^a <= a^b^a*b^a^b.
(Exponentiation associates on the right, so x^y^z = x^(y^z).)
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