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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

1492.0. "Factors of X^n - 1" by CIVAGE::LYNN (Lynn Yarbrough @WNP DTN 427-5663) Thu Sep 12 1991 15:07

Here's an interesting problem, culled from a recent Mathematica text I was 
browsing through:

We note that
x^2 - 1 = (x - 1) (x + 1)
X^3 - 1 = (x - 1) (x^2 + x + 1)
...
x^12 - 1 = 
                          2            2                2    4    2
        (x - 1) (x + 1) (x  + x + 1) (x  - x + 1) (1 + x ) (x  - x  + 1)

etc.

In each of the above examples, all of the polynomial coefficients of each 
factor are either +1, -1, or 0. Is this generally true of the factors of 
X^n - 1 for integer n>0?  You are invited to offer either a proof or a
counterexample. 
T.RTitleUserPersonal
Name
DateLines
1492.1ALLVAX::JROTHI know he moves along the piersFri Sep 13 1991 09:097
     The first counterexample is (x^105-1), because the 105'th
     cyclotomic polynomial is the first one that doesn't have all
     coefficients of -1,0,+1...

     (Stan's masters thesis was on cyclotomic polynomials...)

     - Jim
1492.2what type of poly is cyclotomic ?STAR::ABBASIFri Sep 13 1991 11:541
    what is , please, is cyclotomic polynomials ? 
1492.3ALLVAX::JROTHI know he moves along the piersFri Sep 13 1991 17:386
    Cyclotomy has to do with subdivision of the circle.

    Cyclotomic polynomials are the products of the primitive n'th roots
    of unity.

    - Jim
1492.4HANNAH::OSMANsee HANNAH::IGLOO$:[OSMAN]ERIC.VT240Wed Sep 25 1991 17:001
Don't leave us hanging !  Please factor x^105 - 1.  Thanks.
1492.5MAPLE factors x^105-1CIVAGE::LYNNLynn Yarbrough @WNP DTN 427-5663Wed Sep 25 1991 17:4823
> factor(x^105-1);

          6    5    4    3    2            4    3    2                    5
(x - 1) (x  + x  + x  + x  + x  + x + 1) (x  + x  + x  + x + 1) (1 - x + x

        6    7    8    10    11    12    13    14    16    17    18    19    23
     - x  + x  - x  + x   - x   + x   - x   + x   - x   + x   - x   + x   - x

        24    2                    3    4    6    8    9    11    12
     + x  ) (x  + x + 1) (1 - x + x  - x  + x  - x  + x  - x   + x  )

              3    4    5    7    8            6    5    2      7    24    12
    (1 - x + x  - x  + x  - x  + x ) (1 + x - x  - x  + x  - 2 x  - x   + x

        8    13    14    16    17    9    15    48    20    22    26    28
     - x  + x   + x   + x   + x   - x  + x   + x   - x   - x   - x   - x

        31    32    33    34    35    36    39    40      41    42    43    46
     + x   + x   + x   + x   + x   + x   - x   - x   - 2 x   - x   - x   + x

        47
     + x  )

1492.6Remember SNL's "Great mysteries of the Universe"?VMSDEV::HALLYBFish have no concept of fireWed Sep 25 1991 20:4213
    Thanks, MAPLE & Lynn.  What a shame, a couple of 2s spoil a lonnnng
    series of 0s and 1s.
    
    Which gives rise to the following sorts of questions:
    
    Given k>0, what is the smallest N(k) such that k appears as a
    coefficient in the factorization in X^N - 1?  
    Does N(k) exist for all k?  
    Does the value of k/N(k) converge as k --> oo ?  To what?
    
    In case anyone is looking for a research project...
    
      John
1492.7They're rareCIVAGE::LYNNLynn Yarbrough @WNP DTN 427-5663Thu Sep 26 1991 16:385
I know that "large" (abs value > 1) coefficients are quite rare. N=935 is 
the smallest that I know of that has a k=3. I *think* N has to have at
least 3 distinct prime factors to produce a large one, and even that is not
enough. x^(5*7*11*13)-1 has some 4's and 5's. Fascinating but
time-consuming hobby...