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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

1140.0. "two Friday 13ths this year" by ESCROW::MUNZER () Fri Oct 13 1989 17:53

    
    What percent of years have 2 Friday the 13ths?  0?  1?  3?  4?
    
    John
    
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1140.1AITG::DERAMODaniel V. {AITG,ZFC}:: D'EramoFri Oct 13 1989 23:106
        I think I read that all years have at least one, and
        at most [I can't remember exactly] three or four.  It
        should be easy enough to check, there are only fourteen
        "year types".
        
        Dan
1140.23/7DWOVAX::YOUNGReally DWOVAX::YOUNGSat Oct 14 1989 21:5240
    Well, lets see, a year has one of 2 "shapes":
    
    Normal:		and Leap:
    
    	Jan	0		0
    	Feb	+3		+3
    	Mar	+3		+4
    	Apr	+6		0
    	May	+1		+2
    	Jun	+4		+5
    	Jul	+6		0
    	Aug	+2		+3
    	Sep	+5		+6
    	Oct	0		+1
    	Nov	+3		+4
    	Dec	+5		+6
    
    Where the value after each month is the number of days in the week
    offset from January 1st for the first day of that month.  Thus if
    January 1st fell on a monday, then August 1st would fall on a wenesday
    on a normal year (+2) and on a thursday on a leap year (+3).
    
    When a month has a Friday the 13th in some particular year, then any
    other month will also have a Friday the 13th If and Only If it has the
    same offest value.  Thus we can form groups of months with Friday the
    13th's as follows:
    
    Normal:
    	(Jan,Oct) (Feb,Mar,Nov) (Apr,Jul) (May) (Jun) (Aug) (Sep,Dec)
    
    Leap:
    	(Jan,Apr,Jul) (Feb,Aug) (Mar,Nov) (May) (Jun) (Sep,Dec) (Oct)
    
    So exactly 2 Friday the 13ths will occur 3 out of 7 times in normal
    years and also 3 out of 7 times in leap years.
    
    Thus there is a 3/7 ths chance that there will be exactly 2 Friday the
    13ths in any particular year.
    
    --  Barry
1140.3AITG::DERAMODaniel V. {AITG,ZFC}:: D'EramoSat Oct 14 1989 22:397
        The current calendar cycles through the fourteen possible
        years (two "shapes" times seven start dates per shape)
        every four hundred years.  So the different year types
        don't all occur equally often.  However, your 3/7 should
        be close to the actual x/400 fraction.
        
        Dan
1140.4rightESCROW::MUNZERMon Oct 16 1989 12:123
    Yes, not exactly 3/7.  Like 511.*.
    
    John