Title: | Mathematics at DEC |
Moderator: | RUSURE::EDP |
Created: | Mon Feb 03 1986 |
Last Modified: | Fri Jun 06 1997 |
Last Successful Update: | Fri Jun 06 1997 |
Number of topics: | 2083 |
Total number of notes: | 14613 |
Please see note 249 for background of the following math problem: Consider a hailstorm cycle which takes an odd positive integer to another odd positive integer like this: NEW = (OLD*3+1)/2/2/2/2/2/2/2/2... That is, you divide by 2 as much as necessary to make NEW be odd. Prove that for all positive integers N, there exists a set S(N) of numbers that require at least N cycles to reach the integer 1. For example, try 7. One cycle is (3*7+1)/2, or 11, and two cycles is (3*11+1)/2 or 17, and three cycles is (3*17+1)/4 or 13, and four cycles is (3*13+1)/8 or 5, and five cycles is (3*5+1)/16 or 1. So 7 takes 5 cycles. Hence s(5)={7,...} So for N=5, we've proved the conjecture. Another way of stating the conjecture, is that although the grand conjecture of claiming that all numbers lead to 1 is not proved, perhaps we can prove this simpler conjecture that shows that numbers can be found that lead to 1 but take arbitrarily as long as we like to get there. /Eric
T.R | Title | User | Personal Name | Date | Lines |
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998.1 | KOBAL::GILBERT | Ownership Obligates | Tue Dec 27 1988 11:10 | 14 | |
Let S(N) be the set of odd numbers that require exactly N cycles (as described in .0) to reach the integer 1. Choose an element p of S(N). Suppose p = 3*s+2. Now 2*s+1, 8*s+5, 32*s+21, ..., (2*4^k)*s + (4*4^k-1)/3, ... are all members of S(N+1), because one cycle leads them to p. Suppose p = 3*s+1; now 4*s+1, 16*s+5, ..., (4*4^k)*s + (4*4^k-1)/3, ... are all members of S(N+1). If p = 3*s, there is no value that leads to p in one cycle. However, the above construction shows that for every N, S(N) contains an infinite number of values that aren't multiples of 3. Thus, for any non-empty S(N), the above construction produces an infinite number of elements in S(N+1). By induction, every S(N) contains an infinite number of elements. | |||||
998.2 | New book sheds light | CIVAGE::LYNN | Lynn Yarbrough @WNP DTN 427-5663 | Wed Jun 12 1991 18:13 | 4 |
There's a lot of recent ideas about this problem - and a 'Mathematica' program to investigate it - in the recently published 'Computational Recreations in Mathematica' (Author: Vardi) by Addison-Wesley. Anyone for rewriting it in MAPLE? |