T.R | Title | User | Personal Name | Date | Lines |
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608.1 | help on the way . . . | THEBUS::KOSTAS | Wisdom is the child of experience. | Fri Nov 07 1986 09:22 | 72 |
| Well,
I think the following may help. I have a program that requests for a string
then it requests for the minimum and maximum subsets of the string and it goes and
produces all possible subsets.
ex.
give the string: THIS IS A PHRASE
give the minimum cardinality of the subsets, from = 4
give the maximum cardinality of the subsets, to = 4
13! = 6227020800.00
( 13 - 4)! = 362880.00
4! = 24.00
13!/( 9! 4!) = 715
A list of all 715 possible combinations follows:
THIS THII THIS THIA THIF THIH THIR THIA THIS THIE THEI THIS THSA THAF THFH THHR
THRA THAS THSE THIS THIA THIF THIH THIR THIA THIS THIE THSA THSF THSH THSR THSA
THSS THSE THAF THAH THAR THAA THAS THAE THFH THFR THFA THFS THFE THHR THHA THHS
THHE THRA THRS THRE THAS THAE THSE TSEI TEIS TISA TSAF TAFH TFHR THRA TRAS TASE
TSIS TIIA TIIF TIIH TIIR TIIA TIIS TIIE TISA TSSF TSSH TSSR TSSA TSSS TSSE TSAF
TAAH TAAR TAAA TAAS TAAE TAFH TFFR TFFA TFFS TFFE TFHR THHA THHS THHE THRA TRRS
TRRE TRAS TAAE TASE TEIS TSIA TAIF TFIH THIR TRIA TAIS TSIE TESA TASF TFSH THSR
TRSA TASS TSSE TEAF TFAH THAR TRAA TAAS TSAE TEFH THFR TRFA TAFS TSFE TEHR TRHA
TAHS TSHE TERA TARS TSRE TEAS TSAE TESE TISA TISF TISH TISR TISA TISS TISE TIAF
TIAH TIAR TIAA TIAS TIAE TIFH TIFR TIFA TIFS TIFE TIHR TIHA TIHS TIHE TIRA TIRS
TIRE TIAS TIAE TISE TSAF TSAH TSAR TSAA TSAS TSAE TSFH TSFR TSFA TSFS TSFE TSHR
TSHA TSHS TSHE TSRA TSRS TSRE TSAS TSAE TSSE TAFH TAFR TAFA TAFS TAFE TAHR TAHA
TAHS TAHE TARA TARS TARE TAAS TAAE TASE TFHR TFHA TFHS TFHE TFRA TFRS TFRE TFAS
TFAE TFSE THRA THRS THRE THAS THAE THSE TRAS TRAE TRSE TASE ASEI SEIS EISA ISAF
SAFH AFHR FHRA HRAS RASE ASIS SIIA IIIF IIIH IIIR IIIA IIIS IIIE IISA ISSF SSSH
SSSR SSSA SSSS SSSE SSAF SAAH AAAR AAAA AAAS AAAE AAFH AFFR FFFA FFFS FFFE FFHR
FHHA HHHS HHHE HHRA HRRS RRRE RRAS RAAE AASE AEIS ESIA SAIF AFIH FHIR HRIA RAIS
ASIE SESA EASF AFSH FHSR HRSA RASS ASSE SEAF EFAH FHAR HRAA RAAS ASAE SEFH EHFR
HRFA RAFS ASFE SEHR ERHA RAHS ASHE SERA EARS ASRE SEAS ESAE SESE EISA IISF IISH
IISR IISA IISS IISE IIAF IIAH IIAR IIAA IIAS IIAE IIFH IIFR IIFA IIFS IIFE IIHR
IIHA IIHS IIHE IIRA IIRS IIRE IIAS IIAE IISE ISAF SSAH SSAR SSAA SSAS SSAE SSFH
SSFR SSFA SSFS SSFE SSHR SSHA SSHS SSHE SSRA SSRS SSRE SSAS SSAE SSSE SAFH AAFR
AAFA AAFS AAFE AAHR AAHA AAHS AAHE AARA AARS AARE AAAS AAAE AASE AFHR FFHA FFHS
FFHE FFRA FFRS FFRE FFAS FFAE FFSE FHRA HHRS HHRE HHAS HHAE HHSE HRAS RRAE RRSE
RASE SEIS ISIA IAIF IFIH IHIR IRIA IAIS ISIE IESA SASF SFSH SHSR SRSA SASS SSSE
SEAF AFAH AHAR ARAA AAAS ASAE AEFH FHFR FRFA FAFS FSFE FEHR HRHA HAHS HSHE HERA
RARS RSRE REAS ASAE AESE SISA SISF SISH SISR SISA SISS SISE SIAF AIAH AIAR AIAA
AIAS AIAE AIFH FIFR FIFA FIFS FIFE FIHR HIHA HIHS HIHE HIRA RIRS RIRE RIAS AIAE
AISE SSAF ASAH ASAR ASAA ASAS ASAE ASFH FSFR FSFA FSFS FSFE FSHR HSHA HSHS HSHE
HSRA RSRS RSRE RSAS ASAE ASSE SAFH FAFR FAFA FAFS FAFE FAHR HAHA HAHS HAHE HARA
RARS RARE RAAS AAAE AASE SFHR HFHA HFHS HFHE HFRA RFRS RFRE RFAS AFAE AFSE SHRA
RHRS RHRE RHAS AHAE AHSE SRAS ARAE ARSE SASE EISA AISF FISH HISR RISA AISS SISE
EIAF FIAH HIAR RIAA AIAS SIAE EIFH HIFR RIFA AIFS SIFE EIHR RIHA AIHS SIHE EIRA
AIRS SIRE EIAS SIAE EISE ESAF FSAH HSAR RSAA ASAS SSAE ESFH HSFR RSFA ASFS SSFE
ESHR RSHA ASHS SSHE ESRA ASRS SSRE ESAS SSAE ESSE EAFH HAFR RAFA AAFS SAFE EAHR
RAHA AAHS SAHE EARA AARS SARE EAAS SAAE EASE EFHR RFHA AFHS SFHE EFRA AFRS SFRE
EFAS SFAE EFSE EHRA AHRS SHRE EHAS SHAE EHSE ERAS SRAE ERSE EASE ISAF ISAH ISAR
ISAA ISAS ISAE ISFH ISFR ISFA ISFS ISFE ISHR ISHA ISHS ISHE ISRA ISRS ISRE ISAS
ISAE ISSE IAFH IAFR IAFA IAFS IAFE IAHR IAHA IAHS IAHE IARA IARS IARE IAAS IAAE
IASE IFHR IFHA IFHS IFHE IFRA IFRS IFRE IFAS IFAE IFSE IHRA IHRS IHRE IHAS IHAE
IHSE IRAS IRAE IRSE IASE SAFH SAFR SAFA SAFS SAFE SAHR SAHA SAHS SAHE SARA SARS
SARE SAAS SAAE SASE SFHR SFHA SFHS SFHE SFRA SFRS SFRE SFAS SFAE SFSE SHRA SHRS
SHRE SHAS SHAE SHSE SRAS SRAE SRSE SASE AFHR AFHA AFHS AFHE AFRA AFRS AFRE AFAS
AFAE AFSE AHRA AHRS AHRE AHAS AHAE AHSE ARAS ARAE ARSE AASE FHRA FHRS FHRE FHAS
FHAE FHSE FRAS FRAE FRSE FASE HRAS HRAE HRSE HASE RASE
Enjoy,
Kostas G.
|
608.2 | Algorithms & results | TURRIS::AMARTIN | Alan H. Martin | Sat Nov 08 1986 12:28 | 172 |
| There are four pages following this page. The first contains 613 words of
four or more letters each which are constructed from the phrase "THIS
IS A PHRASE". The second contains 111 three letter words constructed from
those characters. The third contains 32 two letter words, and the fourth
contains 15 one letter words. Unfortunately, the method I used to find
the words forces everything to upper case, so some words may appear to be
duplicated when in fact they are pairs of words with the first in all lower
case, and the second with an initial capital.
I used SUBSTR.B36 on UPORT$:[AMARTIN] on TLE"":: to filter the original
list of words. The search algorithm is separate from all the arcane
I/O considerations in the program. I then used VMS EMACS's regular
expression pattern matching to sort the filtered list on the basis of the
size of words. (I know that finite automata can't count, but I can. I
used ^...$, ^..$ and ^.$ as the the patterns). Not the absolutely most
automated method of accomplishing the desired end, but joining together a
few existing tools with a little interaction beats writing something from
scratch.
Sorry if the verbosity of this answer makes people cast about for reasons to
banish it to JOYOFLEX or something. I don't intend to make a habit of
posting the results of such simple queries here.
AESTII AHEAP AHET AHIR AIAS
AIRA AIRE AIRISH AIRSHIP AIRT
AITESIS APAR APART APER APERT
APHESIS APHETA APHIS APHRA APHRITE
APHTHA APIARIST APII APIS APISH
APSE APSIS APTERA ARATI AREA
ARHAT ARHATSHIP ARIA ARIES ARISE
ARIST ARISTA ARISTEAS ARITE ARSE
ARSES ARSIS ARTHA ARTIE ASAPH
ASARH ASARITE ASEPSIS ASHA ASHER
ASHERAH ASHES ASHET ASHIR ASHPIT
ASITIA ASPER ASPIRATE ASPIRE ASPISH
ASSAI ASSART ASSATE ASSE ASSERT
ASSET ASSETS ASSI ASSIS ASSISE
ASSISH ASSIST ASSISTER ASTA ASTARE
ASTER ASTERIA ASTERIAS ASTIR ATAP
ATES ATHAR ATHERIS ATHREPSIA ATIP
ATIS ATRESIA ATRIA ATRIP EARTH
EAST EATS EPHA EPHAH EPISTASIS
EPITASIS ERIA ERST ERTH ESPRIT
ESTH HAET HAIR HAIRE HAPI
HARASS HARE HARISH HARP HARPA
HARPIST HARSH HART HASH HASHER
HASP HASSAR HASTA HASTE HASTER
HASTISH HATE HATER HATH HATHI
HATI HATRESS HEAP HEAPS HEAR
HEARST HEART HEARTH HEARTS HEAT
HEATH HEII HEIR HEIRSHIP HEIST
HEPAR HERAT HERS HERSHIP HEST
HIATE HIPE HIPER HIPSTER HIRE
HIRSE HISH HISPA HISS HISSER
HIST HISTIE HITHE HITHER IPHIS
IRATE IRIS IRISH ISAIAH ISARIA
ISATIS ISIS ISSEI ISSITE ITEA
ITER ITHER PAAR PAHA PAHARI
PAHI PAIR PAIS PAISA PARA
PARAH PARASITE PARATE PARATHESIS PARE
PARESIS PARI PARIAH PARIES PARIS
PARISH PARISIS PARITI PARSE PARSI
PART PASH PASHA PASI PASS
PASSE PASSE PASSER PASSER PASSIR
PAST PASTA PASTE PASTER PATA
PATAS PATE PATER PATERA PATERISSA
PATESI PATH PATRIA PEAI PEAR
PEART PEAT PERI PERISH PERIT
PERSIS PERSIS PERSIST PERT PERTISH
PESA PESAH PESS PEST PHAET
PHARE PHARISAIST PHASE PHASES PHASIS
PHIT PHRASE PHTHISIS PIARIST PIAST
PIASTER PIASTRE PIER PIERIS PIET
PIETAS PIRATE PIRATESS PISE PISH
PISS PIST PISTIA PITA PITARAH
PITH PITIER PRAISE PRASE PRASTHA
PRAT PRATE PRESS PREST PRIEST
PRIESTISH PRISS PRISTIS PSHA PTERIS
RAASH RAIA RAIA RAIAE RAIS
RAIS RAISE RAPE RAPHE RAPHIA
RAPHIS RAPIST RAPT RASA RASE
RASH RASHTI RASP RASPISH RASPITE
RASSE RATA RATE RATH RATHE
REAP REASSIST REHASH REIS REIT
REPASS REPAST REPS RESH RESHIP
RESIST RESP REST RESTIS RETIA
RETIP RHAPIS RHEA RHEA RIATA
RIPA RIPE RISE RISHI RISP
RISS RIST RITA RITA RITE
SAHH SAIP SAIPH SAIR SAITE
SAITHE SAPA SAPHIE SARA SARAH
SARE SARI SARIP SARSA SARSI
SART SART SARTISH SASA SASH
SATE SATIRE SATRAE SATRAP SATRAPESS
SEAH SEAR SEAT SEIT SEPIA
SEPS SEPSIS SEPT SEPT SEPTA
SEPTI SERA SERAI SERAPH SERAPIAS
SERAPIS SERAPIST SERI SERT SERTA
SESHAT SESIA SESS SESTI SETA
SETARIA SETH SETH SHAH SHAHI
SHAP SHAPE SHAPE SHAPER SHAPS
SHARE SHARESHIP SHARP SHARPIE SHARPISH
SHARPS SHASTA SHASTER SHASTRA SHASTRI
SHAT SHEA SHEAR SHEARS SHEAT
SHEATH SHER SHERIAT SHERPA SHESHA
SHETH SHIAH SHIER SHIES SHIEST
SHIH SHIITE SHIP SHIRE SHIRPIT
SHIRT SHISH SHITA SHITHER SHRAP
SHRIP SHRITE SIER SIESTA SIPE
SIPER SIRE SIRESHIP SIRESS SIRIH
SIRIS SIRPEA SIRSHIP SISE SISH
SISI SISS SIST SISTER SITA
SITAR SITE SITH SITHE SPAE
SPAER SPAHI SPAR SPAR SPARE
SPARSE SPART SPARTH SPAT SPATE
SPATHA SPATHE SPEAR SPEISS SPET
SPIER SPIRAEA SPIRATE SPIRE SPIREA
SPIRIT SPIRT SPISE SPIT SPITE
SPITISH SPRAT SPREATH SPRET SPRIEST
SPRIT SPRITE STAIA STAIR STAP
STAPES STAR STAR STARE STARSHIP
STASES STASH STASHIE STASIS STEP
STERI STIPA STIPE STIPES STIR
STIRP STIRPS STRA STRAE STRAP
STRASS STRE STREPSIS STRESS STRIA
STRIAE STRIP STRIPE TAAR TAHA
TAHR TAIPI TAISE TAPA TAPA
TAPAS TAPE TAPE TAPER TAPHRIA
TAPIA TAPIR TAPIS TAPS TARA
TARAI TARAPH TARASSIS TARE TAREA
TARI TARIE TARISH TARP TARPEIA
TARS TARSE TARSI TARSIA TARSIPES
TASH TASHIE TASS TASS TASSAH
TASSE TASSER TASSIE TEAISH TEAP
TEAR TERA TERAP TERAS TERP
TESS TESSARA THAI THAIS THAPES
THAPSIA THAPSIA THAR THEA THEAH
THEIR THEIRS THERIA THESIS THIASI
THIR THIS THRAEP THRAP THRASH
THREAP THRESH THRIP THRIPS TIAR
TIARA TIER TIPE TIPHIA TIRE
TISAR TISHRI TRAH TRAIPSE TRAP
TRAPA TRAPES TRAPS TRASH TRASHIP
TRASS TRESPASS TRESS TRIAS TRIP
TRIPE TRIPHASE TRIPHASIA TRIPSIS TSAR
TSARSHIP TSHI TSIA
AER AES AHA AHT AIR AIT APA APE APT
ARA ARE ART ART ASA ASE ASH ASP ASS
AST ATA ATE ATI EAR EAT ERA ERS ESS
ETA HAH HAP HAS HAT HEI HEP HER HET
HIA HIE HIP HIS HIT IHI IRA IRE IST
ITA ITS PAH PAR PAS PAT PAT PEA PER
PES PHI PIA PIE PIR PIT PSI PST RAH
RAP RAS RAT REA REH REP RET RHE RIA
RIE RIP RIT SAA SAH SAI SAP SAR SAT
SEA SER SET SHA SHE SHI SIA SIE SIP
SIR SIR SIS SIS SIT SPA SRI SRI TAA
TAE TAI TAI TAP TAR TEA THA THE TIE
TIP TRA TRI
AA AE AH AH AI AR AS AS AT
EA EH ER ES HA HE HI IE IS
IT PA PI RA RE SA SE SH SI
ST TA TE TH TI
A E E H H I I P P
R R S S T T
|
608.3 | computers can read entire dictionary with no problem | REGINA::OSMAN | and silos to fill before I feep, and silos to fill before I feep | Mon Nov 10 1986 16:19 | 16 |
| If you want to know all the words you can find in a phrase such as
"THIS IS A PHRASE", it is silly on a computer to do it "like we do",
namely shuffle letters around, and see what combinations come up as
words.
In other words, it is silly to ask the computer to generate all
combinations of the original phrase and then see which are words.
THE BETTER SENSIBLE IDEA :
Program the computer to scan its on-line dictionary *ONCE*,
and for each word in it, see if the word can be made with
"THIS IS A PHRASE", and print it out if so. Such a loop
runs quite quickly and tells you the whole answer.
/Eric
|
608.4 | Oooooh! | AYOV10::FBRIDGEFORD | Fraser Bridgeford | Tue Nov 11 1986 09:48 | 5 |
| A touch of brilliance, thank you. Now to find whose got the Shorter
Oxford or the Websters on line. I'll go ask elsewhere
thanks very much.
Fraser_B
|
608.5 | Elaborate; good luck | TURRIS::AMARTIN | Alan H. Martin | Tue Nov 11 1986 10:03 | 9 |
| Re .3:
Was your comment directed at some note in particular?
Re .4:
You get a cookie (excuse me, "scone") if you find more words than the
list in .2.
/AHM
|
608.6 | | VINO::JMUNZER | | Mon Jan 05 1987 17:44 | 6 |
| Re .2, .5: Are a few suffixed words missing (parties, hastier, harshest,
prissiest)?
Re .2, .3, .4: What online dictionaries are available?
John
|
608.7 | Might be missing "suffixed" words; one dictionary source | NOBUGS::AMARTIN | Alan H. Martin | Tue Jan 06 1987 08:31 | 13 |
| Re .6:
Dictionaries I have used might well be missing some "suffixed" words,
though none of them contain data on how to add such words to them (unlike a
dictionary I saw in college, which represented words compactly with some
kind of affix expression language).
I made my smaller dictionary by merging dumped lists from SPELL and
WORDS on the -20. I hadn't tried hard to get ISPELL to dump its guts.
You should have the same access to such programs down in PDP-10 land
that I did at the time.
/AHM
|
608.8 | | GAMGEE::ROBR | Sailing the seas of cheeze... | Tue Nov 12 1991 11:48 | 25 |
|
Here is a really simple problem for most of you...
I'm trying to help my girlfriend with her homework but it's been ages
since I've done these things. She gave me 15 word problems. I solved
14 of them but this last one has me stumped...
Mr. Peobody leaves his laboratory to drive to his wayback machine. He
travels at 55mph. He is 10 miles from his lab when Sherman realizes
that Peobody forgot his royal fizzbin. How fast will Sherman have to
drive to catch up with Peobody in two hours?
Also, I'll throw this one in just to make sure I'm doing them right
(I'm pretty sure this was fine, but always worth doublechecking)
Spock has 50 grams of substance that is 7.8% antimatter. How much
substance that is 0% antimatter will he have to add to make the total
strength of antimatter 2%?
I said 7.8(50)+0y=2(50+y)
390=100+2y
2y=290
y=145 grams
|
608.9 | Is this math or physics | PULPO::BELDIN_R | Pull us together, not apart | Tue Nov 12 1991 12:58 | 6 |
| re .8 (antimatter)
Did you consider the matter-anti-matter reaction which converts all of
the anti-matter and a matching mass of matter into energy?
Dick
|
608.10 | And I always thought the way-back was AT the lab! | VMSDEV::HALLYB | Fish have no concept of fire | Tue Nov 12 1991 13:18 | 11 |
| Ignoring the laws of physics, the "antimatter" answer looks correct.
As far as Sherman goes, look at it this way: Peabody is 10 miles away.
In two hours Peabody will be 10+55*2=120 miles away. How fast will
Sherman have to drive to cover 120 miles in 2 hours? You take it from
there, but remember you are assuming acceleration from 0 to the answer
in 0 time -- again violating the laws of physics.
Who writes these books anyway?
John
|
608.11 | ah ha.. 55(2)+10=2x where x is sherman's speed | GAMGEE::ROBR | Sailing the seas of cheeze... | Tue Nov 12 1991 13:39 | 15 |
|
Actually those werent the original problems, I changed them to protect
the innocent (Dr. White and a cow) :').Dr. White still intends to
violate the acceleration principle anyway :').
Okay, so um, er... how can Mr. Peobody be written in an
x = shermans speed type of format? (thats how the U Lowell prof. wants
it done I guess). Let me see...
scrap paper time...
thanks for all the help! :')
|
608.12 | | ZFC::deramo | I've seen it raining fire in the sky. | Tue Nov 12 1991 15:15 | 5 |
| What is wrong with wording the answer to the "how fast"
question as "He must travel at an average speed of ..."?
No more problems with instantaneous acceleration.
Dan
|
608.13 | | WDFRT1::JUNKER::RABAHY | dtn 471-5160 | Wed Nov 13 1991 09:03 | 10 |
| RE: .10
I've never been quite happy with the acceleration issue. Yes,
accelerating from 0 to a speed in 0 time is forbidden - not just
from 0 to 60 mph, but for any finite speed. So, how the heck does
anything get moving at all? This seems to be a cousin of Zeno's
paradox. I'de take this up in the physics conference but I'de kinda
like to sort out the mathematics first before worrying about the real
world. I'm sure the answer lies in the study of limits and
infinitesimals.
|
608.14 | Acceleration and velocity are different.. | GIDDAY::FERGUSON | Murphy was an optimist | Thu Nov 14 1991 07:04 | 33 |
| Re: <.13>
I think you're confusing acceleration and velocity. Acceleration is the rate
of change in velocity, with respect to time; while velocity is the rate of
change in distance with respect to time (both are vector quantities). Thus, for
a body travelling in a straight line with constant acceleration A (say 10
metres/sec�) its velocity V is the antiderivative of its acceleration, and the
total distance travelled, D is the antiderivative of the velocity, i.e.
A = 10
V = 10t
and D = 5t� (where t = time in seconds)
Any increase in velocity takes time. After 0 seconds (t=0) the object is still
stationery, since its velocity is then 10 x 0 = 0. At any given instant later,
(since its acceleration is constant) its velocity may be calculated as a linear
function of the time since it started moving, i.e. since its acceleration was
0. At the end of one second, its velocity will be 10 metres/sec, and it will
have covered a distance of 5 metres; after 2 seconds its velocity is 20
metres/sec and it will also have travelled 20 metres - its average velocity at
this time will be 1 metre/sec. Since the body is accelerating constantly
(and was motionless when it began, i.e. when its acceleration was 0) its
average velocity will continue to increase, linearly as a function of time.
There's nothing much mysterious about this. Velocity does not increase "in
no time at all", other than the instant when inertia and friction etc. are
overcome and the body is set in motion, when its acceleration and velocity
become non-zero simultaneously. Does this help or have I only added to
your confusion?
James.
|
608.15 | | WDFRT1::JUNKER::RABAHY | dtn 471-5160 | Thu Nov 14 1991 13:54 | 11 |
| RE: .14
I assure you I am not confusing acceleration and velocity. I
appreciate your clear explaination. At only two points did you loose
me. Both times you wrote that the acceleration 0, not 10. I suppose
these might simply be typos. In your example, at time 0, what is the
acceleration?
Your final paragraph gets to the heart of the matter. You wrote, "...
other than the instant when ...". It is exactly that moment that I am
most interested in. My confusion remains constant on this point.
|
608.16 | | WDFRT1::JUNKER::RABAHY | dtn 471-5160 | Thu Nov 14 1991 14:00 | 8 |
| RE: .14
Okay, I think I understand. Your last paragraph says the velocity and
acceleration both become non-zero together. So, then, does the
acceleration jump from 0 to the constant 10 all at once? Or is there
some sort of hyper-acceleration? The acceleration increases from 0 to
10 a such and such a rate. Once the acceleration reaches the value of
10 it is held constant.
|
608.17 | Acceleration can jump. | CADSYS::COOPER | Topher Cooper | Thu Nov 14 1991 15:06 | 53 |
| RE: .16
Velocity (at least in classical mechanics) cannot be discontinuous. If
there is one time t0 at which something is moving at velocity v0 and
another time t1 at which it is moving at velocity v1, then for any
velocity vx between v0 and v1 there must be a time, tx between t0 and
t1 at which the thing is moving at velocity vx. In other words if
you plot velocity against time there will be no perfectly vertical
steps.
Sometimes it is convenient to ignore that restriction. If there is
a very large but very short accleration it may simplify things to
treat it as an instantaneous, discontinuous change in velocity.
There is generally no such continuity restriction placed on
acceleration, and so it is common, even usual to assume instanteous,
discontinuous changes in acceleration. If you think about it, most
(all?) examples of changes of acceleration are actually continuous
but very rapid. But very, very, rapid changes of acceleration are
so commonplace (for example, the deceleration of a hard ball slamming
into a hard wall) that the utility of discontinuous descriptions is
almost universal.
There is a term used occasionally for the rate of change of
acceleration, but it is so rarely used that I have forgotten what it
is called (its a common word pulled into technical service). I have
seen as an academic exercise an attempt to define the names of still
higher derivatives but I doubt that anyone has every really,
unselfconsciously used them.
The reason that the rate of change of velocity has a common name but
the rate of change of acceleration does not is that acceleration has
a fundamental role in mechanics -- in classical physics it figures
in the definition of force, and in GR it has an even more fundamental
role. Higher order derivatives are simply descriptive of a particular
situation, and do not appear in descriptions of fundamental laws.
You could probably, if you wished, define a coherent completely
continuous mechanics, where all problems are defined by changes in
position which are continuous for all orders of derivative. Your
problem statements will then become unnecessarily complex at no
particular gain.
The answer to questions such as you've been asking would then be by
reference to the next higher derivative of position over time for still
smaller time periods, and so on for an infinite regress. It would
then, like Zeno's paradox, ulitimately be resolved by reference to a
limit. In virtually all cases, that limit would be in almost all cases
the same as if you just stopped at acceleration. Easier to simply say
that both continuous and discontinuous changes in acceleration (and
higher derivatives when occasionally needed) are "allowed".
Topher
|
608.18 | Four! (this is the Math conf.) | CIVAGE::LYNN | Lynn Yarbrough @WNP DTN 427-5663 | Thu Nov 14 1991 15:24 | 23 |
| Maybe it will help to consider what happens to a golf ball when driven by a
club. As you swing the club, it attains a certain velocity - say 50 MPH;
when it hits the ball, it decellerates a bit and loses perhaps 5% of its
velocity as you begin your follow-through.
During the time that the club face is in contact with the ball, the ball
experiences a *huge* momentary acceleration that causes it to go from 0 to
about 90 MPH in a fraction of a second. The accelerative force is so great
that it distorts the shape of the ball, but as soon as the ball leaves the
club face the acceleration drops immediately back to zero, while the
velocity continues - air friction slows it down a bit. Acceleration affects
the ball only for a fraction of a second, but the velocity remains until
some other force - friction with air or ground, or hitting a tree or
something - causes decelleration again. If you calculate the acceleration
that the driver causes, you come up with thousands of feet/sec^2, but the
actual duration is on the order of milliseconds.
The velocity figures above may seem strange, but the ball actually is
moving faster than the club head because as the ball returns to its
original shape while still in contact with the club head, it continues to
accelerate. The club-ball contact also distorts the shape of the club
shaft, and its restoration also speeds up the ball (graphite clubs are
better because they restore faster).
|
608.19 | Remember the Quantum | PULPO::BELDIN_R | Pull us together, not apart | Thu Nov 14 1991 16:19 | 13 |
| re .17
>You could probably, if you wished, define a coherent completely
>continuous mechanics, where all problems are defined by changes in
>position which are continuous for all orders of derivative.
But of course, it wouldn't be realistic. Continuity is just a
convenient approximation for huge numbers of tiny jumps.
fwiw,
Dick
|
608.20 | | ZFC::deramo | Be excellent to each other. | Thu Nov 14 1991 16:39 | 11 |
| re .17,
> There is a term used occasionally for the rate of change of
> acceleration, but it is so rarely used that I have forgotten what it
> is called (its a common word pulled into technical service).
3 3
I have heard the unit of measurement of d s/dt (or da/dt) referred
to as the "jerk," with 1 jerk = 1 meter per cubic second. :-)
Dan
|
608.21 | They're so much better than the spherical ones. | CADSYS::COOPER | Topher Cooper | Thu Nov 14 1991 16:58 | 8 |
| RE: .20
3 3
>I have heard the unit of measurement of d s/dt (or da/dt) referred
>to as the "jerk," with 1 jerk = 1 meter per cubic second. :-)
Now where did I leave my cubic second? -- I had it just a moment ago.
Topher :-)
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608.22 | Measured with a cubic clock | HIBOB::SIMMONS | Tristram Shandy as an equestrian | Thu Nov 14 1991 17:27 | 1 |
| That like one of those clocks with four faces? :-)
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608.23 | Look at increments | SNOC02::WATTS | | Mon Nov 18 1991 19:40 | 12 |
| The example in .8 can also be solved without reference to the actual
speed of the original tourist - the incremental distance to be
travelled in two hours (the chase time) is 10 miles (the tourist's
lead), so the incremental speed is 5 mph.
Speed of original tourist is 55 mph (isn't that some kind of magic
number in the US for roads?), thus the chaser needs to travel at 60.
Its easier in metric ;>)
regards,
Michael Watts.
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