Title: | Mathematics at DEC |
Moderator: | RUSURE::EDP |
Created: | Mon Feb 03 1986 |
Last Modified: | Fri Jun 06 1997 |
Last Successful Update: | Fri Jun 06 1997 |
Number of topics: | 2083 |
Total number of notes: | 14613 |
The question is often asked: "If a hoop that fits perfectly around the earth's equator is cut and lengthened by inserting one inch, will it still fit so tightly that even a knife blade cannot be slipped under it?" Enjoy, Kostas G.
T.R | Title | User | Personal Name | Date | Lines |
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495.1 | An inch goes a long ways! | VAXRT::BRIDGEWATER | Sun Jun 01 1986 00:39 | 6 | |
No. If the equator and hoop encircling it are both assumed to be circles, the hoop after having been lengthened by an inch will have a little less than 1/6 (1/2pi) inch clearance above the equator at every point on the equator. - Don | |||||
495.2 | Some calculations related... | THEBUS::KOSTAS | Kostas G. Gavrielidis <o.o> | Tue Jun 03 1986 09:27 | 27 |
The inch seems so small an addition to the equator's twenty five thousand miles, that a hasty judgement often leads to an affirmative answer to this question. Let's see, if the earth's circumference is C inches and the radius is R inches, then 2*(pi)*R = C and R = C/(2*pi). When the circumference is increased to C+1 inches, the radius is incresed to (C+1)/(2*pi), more by 1/(2*pi) inches or .159 inches. So the lengthened hoop could be raised more than 1/8 of an inch all around the equator. Note: The same amount of raising occurs when one inch is added to any hoop, however large or small. Enjoy, Kostas G. |