| Title: | Mathematics at DEC |
| Moderator: | RUSURE::EDP |
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
A reasonable-sounding theorem is this: If each side of triangle A is larger than the corresponding side of triangle B, then triangle A has larger area than triangle B. Unfortunately, this is false. Exhibit a counter-example.
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 384.1 | BEING::RABAHY | Thu Nov 21 1985 09:41 | 4 | ||
The area of the triangle with sides 3, 4 and 5 is 6, whereas one with sides sqrt(26), sqrt(26) and 10 is 5. David. | |||||
| 384.2 | PIPER::REILLY | Thu Nov 21 1985 09:58 | 13 | ||
In general, given a triangle with sides a, b, and c, a second triangle can be constructed with sides w, x, and y such that w = a + d x = b + d y = a + b + 2d Note that the second triangle has area ZERO. If you want a proper triangle, subtract some epsilon from the length of y to get and area > 0 and less than that of the first triangle. matt | |||||