Title: | Mathematics at DEC |
Moderator: | RUSURE::EDP |
Created: | Mon Feb 03 1986 |
Last Modified: | Fri Jun 06 1997 |
Last Successful Update: | Fri Jun 06 1997 |
Number of topics: | 2083 |
Total number of notes: | 14613 |
We need more problems in this file. Here is one: Find all rational numbers q such that: n ----- \ n i / ( )(q-1) = 1/1024, where n is an integer. ----- i i=0 (The above equation says the sum for all integer values of i from 0 to n, inclusive, of the number of combinations of n things taken i at a time multiplied by (q-1) to the power of i is 1/1024.) This was a problem in a high school competition. The time limit is six minutes (although it was one of the hardest problems, so more time is reasonable). -- edp
T.R | Title | User | Personal Name | Date | Lines |
---|---|---|---|---|---|
333.1 | BEING::POSTPISCHIL | Sat Sep 21 1985 19:43 | 12 | ||
No takers yet? A hint follows the form-feed. n ----- \ n i n-i n / ( )p q = (p+q) ----- i i=0 -- edp | |||||
333.2 | TAV02::NITSAN | Sun Sep 22 1985 07:34 | 15 | ||
n n ----- ----- \ n i \ n i n-i n n 1/1024 = / ( )(q-1) = / ( )(q-1) 1 = (q-1+1) = q ----- i ----- i i=0 i=0 n _____ n ______ / / 10 So, q = \/1/1024 = \/(1/2) which is rational for n=1,2,5,10 and yields: q = 1/1024, 1/32, 1/4, 1/2 Nitsan. | |||||
333.3 | ALIEN::POSTPISCHIL | Mon Sep 23 1985 10:19 | 7 | ||
Re .2: Very good, but you forgot (as I did, originally, as well as the creator of the problem) -1/32 and -1/2. -- edp |